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©2006-2009 ~acornah
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Submitted: November 12, 2006
Image Size: 83.6 KB
Resolution: 650×500
Comments: 11
Favourites & Collections: 112 [who?]

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Artist's Comments

This was for Nikkayla at nshc-studio.net. It's kind of a demon-horse, so to speak. The wings are from a fruit bat, the horn from some sort of antelope, the tail from a lioness, and the clawed feet are from a toy T Rex model (lol!). It was great fun playing with the lighting on this one. It's not really noticeable, but there are bits of shadow in the fog where the horse's shadow falls.
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Comments


Haha, I am forced to fav all your pics because of their incredible smexxiness. I love how you did the shadows on the fog...I wouldn't even have thought of that but it adds a lot a realism.

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Just be yourself, if you have to change to make people love you, then they don't love YOU they love the person they want you to be.
looks very good!

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"Life's not like the movies. There's no script that says the good guys have to win."
ohmygawwwd. that is incredible. :D I love your style, great job. :hug:

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friends ask you why your crying, but best friends already have the shovel to bury the asshole that mad you cry..





->my gallery<-


Thanks for the comment. ^_^ I wish all my manips would work out like this one did.

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"I used to have Mad Cow's disease, but I'm alright Nooooooooow."
~Billy Connolly

[link] <-- My wing stock account.
WOW I have had ideas of creating something like a demon horse for ages but have never been able to acheive it.... this is by far completely amazing! Im really loving your gallery!

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clear l i q u o r and c l o u d y eyes...
it's too early to say goodnight...

you have stolen my heart
Remarkable! :clap:

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Logic? Who's That?
I'm so glad you like it! You should give the demon-horse thing a shot, it's really not that hard once you've found nice source pics. ^_^

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"I used to have Mad Cow's disease, but I'm alright Nooooooooow."
~Billy Connolly

[link] <-- My wing stock account.
Nice work.

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Did you know that:

E^2= (p^2c^2)+([<delta>m^2]c^4).
which implies that:
E= [mc^2]/[<sq. root> 1-(v^2/c^2)].
when p=0 (in eq 1, or in 2 rearranged [giving 1])
E=mc^2.
[In reality, p can never=0, so E should, realistically not be =mc^2].
W . O . W
verry nice ! love it! :D

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Love is a Battlefield
xxx
Lynnii

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